How to use getExceptionType method of org.openqa.selenium.remote.ErrorCodes class

Best Selenium code snippet using org.openqa.selenium.remote.ErrorCodes.getExceptionType

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...91 return response;92 }93 94 private WebDriverException createException(String error, String message) {95 Class<? extends WebDriverException> clazz = errorCodes.getExceptionType(error);96 try97 {98 Constructor<? extends WebDriverException> constructor = clazz.getConstructor(new Class[] { String.class });99 return (WebDriverException)constructor.newInstance(new Object[] { message });100 } catch (ReflectiveOperationException e) {101 throw new WebDriverException(message);102 }103 }104}...

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getExceptionType

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1import org.openqa.selenium.remote.ErrorCodes;2public class GetExceptionType {3 public static void main(String[] args) {4 ErrorCodes errorCodes = new ErrorCodes();5 String exceptionType = errorCodes.getExceptionType(7);6 System.out.println("Exception type: " + exceptionType);7 }8}

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getExceptionType

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1package com.selenium4beginners.java.exceptions;2import java.io.File;3import java.io.IOException;4import java.util.concurrent.TimeUnit;5import org.openqa.selenium.By;6import org.openqa.selenium.WebDriver;7import org.openqa.selenium.WebElement;8import org.openqa.selenium.chrome.ChromeDriver;9import org.openqa.selenium.remote.ErrorCodes;10public class GetExceptionType {11 public static void main(String[] args) throws IOException {12 WebDriver driver;13 System.setProperty("webdriver.chrome.driver", "src/​main/​resources/​chromedriver.exe");14 driver = new ChromeDriver();15 driver.manage().window().maximize();16 driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);17 WebElement btnDownload = driver.findElement(By.linkText("Downloads"));18 btnDownload.click();19 WebElement linkVersion = driver.findElement(By.linkText("3.141.59"));20 linkVersion.click();21 ErrorCodes err = new ErrorCodes();22 String errType = err.getExceptionType(new Throwable());23 System.out.println("Exception Type: " + errType);24 Screenshot ss = new Screenshot();25 File scrFile = ss.getScreenshot(driver, "ExceptionType");26 System.out.println("Screenshot saved at: " + scrFile.getAbsolutePath());27 driver.quit();28 }29}

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getExceptionType

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1import org.openqa.selenium.remote.ErrorCodes;2public class ErrorCodesDemo {3 public static void main(String[] args) {4 ErrorCodes errorCodes = new ErrorCodes();5 System.out.println("error code for given exception is: "+errorCodes.getExceptionType("org.openqa.selenium.NoSuchElementException"));6 System.out.println("error message for given error code is: "+errorCodes.getErrorMessage(7));7 System.out.println("error type for given error message is: "+errorCodes.getErrorType("no such element"));8 System.out.println("error class for given error type is: "+errorCodes.getErrorClass("NoSuchElement"));9 System.out.println("exception type for given error class is: "+errorCodes.getExceptionType("org.openqa.selenium.NoSuchElementException"));10 }11}

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getExceptionType

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1package com.selenium;2import org.openqa.selenium.remote.ErrorCodes;3public class GetExceptionType {4 public static void main(String[] args) {5 ErrorCodes errorCodes = new ErrorCodes();6 String exceptionType = errorCodes.getExceptionType(7);7 System.out.println(exceptionType);8 }9}

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getExceptionType

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1import org.openqa.selenium.remote.ErrorCodes;2public class ExceptionTypeFromErrorCode {3 public static void main(String[] args) {4 ErrorCodes errorCodes = new ErrorCodes();5 String exceptionType = errorCodes.getExceptionType(13);6 System.out.println(exceptionType);7 }8}

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StackOverFlow community discussions

Questions
Discussion

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Test if an element is present using Selenium WebDriver

Like you said since the xpath for the next button is the same on every page it won't work. It's working as coded in that it does wait for the element to be displayed but since it's already displayed then the implicit wait doesn't apply because it doesn't need to wait at all. Why don't you use the fact that the url changes since from your code it appears to change when the next button is clicked. I do C# but I guess in Java it would be something like:

WebDriver driver = new FirefoxDriver();
String startURL = //a starting url;
String currentURL = null;
WebDriverWait wait = new WebDriverWait(driver, 10);

foo(driver,startURL);

/* go to next page */
if(driver.findElement(By.xpath("//*[@id='someID']")).isDisplayed()){
    String previousURL = driver.getCurrentUrl();
    driver.findElement(By.xpath("//*[@id='someID']")).click();  
    driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);

    ExpectedCondition e = new ExpectedCondition<Boolean>() {
          public Boolean apply(WebDriver d) {
            return (d.getCurrentUrl() != previousURL);
          }
        };

    wait.until(e);
    currentURL = driver.getCurrentUrl();
    System.out.println(currentURL);
} 
https://stackoverflow.com/questions/16242340/selenium-get-current-url-after-loading-a-page

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