How to use calculateInsertionCostOnFirstRow method of org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.CostMatrix class

Best EvoMaster code snippet using org.evomaster.client.java.instrumentation.coverage.methodreplacement.regex.CostMatrix.calculateInsertionCostOnFirstRow

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...69 * 1) deletions followed by replacement70 * 2) as above, and then followed by insertions71 */​72 final double[][][] matrix = new double[ROWS][COLUMNS][3];73 calculateInsertionCostOnFirstRow(graph, matrix);74 for (int i = 1; i < ROWS; i++) {75 for (int col = 0; col < COLUMNS; col++) {76 /​*77 * unless a path is explicitly updated, it will have maximum distance by default78 */​79 matrix[i][col][DEL] = Double.MAX_VALUE;80 matrix[i][col][REP] = Double.MAX_VALUE;81 matrix[i][col][INS] = Double.MAX_VALUE;82 for (GraphTransition t : graph.getIncomingTransitions(i, col)) {83 int otherCol = graph.getColumn(t.fromState);84 int otherRow = t.fromRow;85 if (t.type.equals(GraphTransition.TransitionType.INSERTION)) {86 assert otherRow == i;87 /​*88 * if we have an insertion, only the insertion path can be continued.89 * that's the reason why on the left side we only update for [INS].90 * An insertion can continue any type of path (and so all types are present on the right side).91 */​92 matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));93 matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][REP], t.cost));94 matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][INS], t.cost));95 } else if (t.type.equals(GraphTransition.TransitionType.REPLACEMENT)) {96 /​*97 * if we have a replacement, then we cannot continue a delete path.98 * So, no [DEL] on the left side.99 * A replacement can continue a delete or replace path, but not an insertion one (and so [DEL] and100 * [REP] on right side)101 */​102 matrix[i][col][REP] = Math.min(matrix[i][col][REP], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));103 matrix[i][col][REP] = Math.min(matrix[i][col][REP], getSubPathCost(matrix[otherRow][otherCol][REP], t.cost));104 /​*105 * from this state on, an insertion path can be followed, with same cost (ie right side) as replacement path106 */​107 matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));108 matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][REP], t.cost));109 } else if (t.type.equals(GraphTransition.TransitionType.DELETION)) {110 /​*111 * deletion can only follow a deletion path (so only [DEL] or right side).112 * but, from this state on, any new path can be followed (so all on left side)113 */​114 matrix[i][col][DEL] = Math.min(matrix[i][col][DEL], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));115 matrix[i][col][REP] = Math.min(matrix[i][col][REP], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));116 matrix[i][col][INS] = Math.min(matrix[i][col][INS], getSubPathCost(matrix[otherRow][otherCol][DEL], t.cost));117 } else if (t.type.equals(GraphTransition.TransitionType.PHANTOM)) {118 assert t.cost == 0;119 /​*120 * artificial transition to final/​sink state, so just take same values as previous state121 */​122 matrix[i][col][DEL] = Math.min(matrix[i][col][DEL], matrix[otherRow][otherCol][DEL]);123 matrix[i][col][REP] = Math.min(matrix[i][col][REP], matrix[otherRow][otherCol][REP]);124 matrix[i][col][INS] = Math.min(matrix[i][col][INS], matrix[otherRow][otherCol][INS]);125 }126 }127 }128 /​*129 * TODO: The algorithm of Myers's paper, at page 12, makes a distinction between D and E transitions.130 * Insertions of type E are done last. Not fully clear if it has an effect here: ie, recall that131 * here we do minimization (calculate distance) and not maximization (similarity)132 */​133 }134 /​*135 * get the minimum among the 3 different paths in the sink state136 */​137 double min = Double.MAX_VALUE;138 for (double value : matrix[ROWS - 1][COLUMNS - 1]) {139 if (value < min) {140 min = value;141 }142 }143 return min;144 }145 /​**146 * We cannot just do previousStateCost + transitionCost, as there might be computational overflows147 *148 * @param previousStateCost149 * @param transitionCost150 * @return151 * @throws IllegalArgumentException152 */​153 private static double getSubPathCost(double previousStateCost, double transitionCost) throws IllegalArgumentException {154 if (previousStateCost < 0) {155 throw new IllegalArgumentException("previousStateCost cannot be negative: " + previousStateCost);156 }157 if (transitionCost < 0) {158 throw new IllegalArgumentException("transitionCost cannot be negative: " + transitionCost);159 }160 if (previousStateCost == Double.MAX_VALUE || transitionCost == Double.MAX_VALUE) {161 return Double.MAX_VALUE;162 }163 double sum = previousStateCost + transitionCost;164 if (sum < previousStateCost || sum < transitionCost) {165 /​*166 * likely overflow167 */​168 return Double.MAX_VALUE;169 }170 return sum;171 }172 /​**173 * First row is special, ie very different from the others174 *175 * @param graph176 * @param matrix177 */​178 private static void calculateInsertionCostOnFirstRow(RegexGraph graph, final double[][][] matrix) {179 /​/​ First row is cost of matching empty sequence on regex180 final int FIRST_ROW = 0;181 /​*182 * init first starting state with 0 costs183 */​184 matrix[FIRST_ROW][0][0] = 0;185 matrix[FIRST_ROW][0][1] = 0;186 matrix[FIRST_ROW][0][2] = 0;187 for (int col = 1; col < graph.getNumberOfColumns(); col++) {188 double min = Double.MAX_VALUE;189 for (GraphTransition t : graph.getIncomingTransitions(FIRST_ROW, col)) {190 /​*191 * on first row, there can be only insertions coming from the same row,192 * apart from last node that can have a phantom transition to sink state...

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calculateInsertionCostOnFirstRow

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1public class CostMatrix {2 public static void main(String[] args) {3 int[][] matrix = new int[4][4];4 matrix[0][0] = 0;5 matrix[0][1] = 1;6 matrix[0][2] = 2;7 matrix[0][3] = 3;8 matrix[1][0] = 1;9 matrix[1][1] = 0;10 matrix[1][2] = 1;11 matrix[1][3] = 2;12 matrix[2][0] = 2;13 matrix[2][1] = 1;14 matrix[2][2] = 0;15 matrix[2][3] = 1;16 matrix[3][0] = 3;17 matrix[3][1] = 2;18 matrix[3][2] = 1;19 matrix[3][3] = 0;20 int cost = CostMatrix.calculateInsertionCostOnFirstRow(matrix);21 System.out.println("Cost of insertion of a character on the first row of the matrix is " + cost);22 cost = CostMatrix.calculateDeletionCostOnFirstColumn(matrix);23 System.out.println("Cost of deletion of a character on the first column of the matrix is " + cost);24 }25 public static int calculateInsertionCostOnFirstRow(int[][] matrix) {26 int cost = 0;27 for (int i = 0; i < matrix[0].length; i++) {28 cost += matrix[0][i];29 }30 return cost;31 }32 public static int calculateDeletionCostOnFirstColumn(int[][] matrix) {33 int cost = 0;34 for (int i = 0; i < matrix.length; i++) {

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calculateInsertionCostOnFirstRow

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1public class ExampleController {2 public int calculateInsertionCostOnFirstRow(String a, String b) {3 return CostMatrix.calculateInsertionCostOnFirstRow(a, b);4 }5}6package org.evomaster.core.problem.rest.controller;7import com.foo.ExampleControlle

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calculateInsertionCostOnFirstRow

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1public void testInsertionCostOnFirstRow() {2 String[] patterns = new String[]{"a", "b"};3 String[] strings = new String[]{"a", "b"};4 CostMatrix matrix = new CostMatrix(patterns, strings);5 int cost = matrix.calculateInsertionCostOnFirstRow();6 assertEquals(2, cost);7}8public void testDeletionCostOnFirstColumn() {9 String[] patterns = new String[]{"a", "b"};10 String[] strings = new String[]{"a", "b"};11 CostMatrix matrix = new CostMatrix(patterns, strings);12 int cost = matrix.calculateDeletionCostOnFirstColumn();13 assertEquals(2, cost);14}15public void testSubstitutionCostOnFirstRow() {16 String[] patterns = new String[]{"a", "b"};17 String[] strings = new String[]{"a", "b"};18 CostMatrix matrix = new CostMatrix(patterns, strings);19 int cost = matrix.calculateSubstitutionCostOnFirstRow();20 assertEquals(0, cost);21}22public void testSubstitutionCostOnFirstColumn() {23 String[] patterns = new String[]{"a", "b"};24 String[] strings = new String[]{"a", "b"};25 CostMatrix matrix = new CostMatrix(patterns, strings);26 int cost = matrix.calculateSubstitutionCostOnFirstColumn();27 assertEquals(0, cost);28}

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calculateInsertionCostOnFirstRow

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1CostMatrix costMatrix = new CostMatrix(1);2String regex = "a{2}";3int cost = costMatrix.calculateInsertionCostOnFirstRow(regex);4assert cost == 2;5regex = "a{3}";6cost = costMatrix.calculateInsertionCostOnFirstRow(regex);7assert cost == 3;8regex = "a{4}";9cost = costMatrix.calculateInsertionCostOnFirstRow(regex);10assert cost == 4;11regex = "a{5}";12cost = costMatrix.calculateInsertionCostOnFirstRow(regex);13assert cost == 5;14regex = "a{6}";15cost = costMatrix.calculateInsertionCostOnFirstRow(regex);16assert cost == 6;17regex = "a{7}";18cost = costMatrix.calculateInsertionCostOnFirstRow(regex);19assert cost == 7;20regex = "a{8}";21cost = costMatrix.calculateInsertionCostOnFirstRow(regex);22assert cost == 8;23regex = "a{9}";

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