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How to use retainAll method of org.assertj.core.presentation.StandardRepresentation_toStringOf_Test class

Best Assertj code snippet using org.assertj.core.presentation.StandardRepresentation_toStringOf_Test.retainAll

Source: StandardRepresentation_toStringOf_Test.java

...428    public boolean removeAll(Collection<?> c) {429      return list.removeAll(c);430    }431    @Override432    public boolean retainAll(Collection<?> c) {433      return list.retainAll(c);434    }435    @Override436    public void clear() {437      list.clear();438    }439    @Override440    public T get(int index) {441      return list.get(index);442    }443    @Override444    public T set(int index, T element) {445      return list.set(index, element);446    }447    @Override...

retainAll

Using AI Code Generation

1public class StandardRepresentation_toStringOf_Test {2    public void should_return_toString_of_given_object() {3        Object o = new Object();4        String s = toStringOf(o);5        assertThat(s).isEqualTo(o.toString());6    }7    public void should_return_toString_of_given_array() {8        Object[] o = new Object[]{ "foo", "bar" };9        String s = toStringOf(o);10        assertThat(s).isEqualTo("[foo, bar]");11    }12    public void should_return_toString_of_given_array_with_null_element() {13        Object[] o = new Object[]{ "foo", null };14        String s = toStringOf(o);15        assertThat(s).isEqualTo("[foo, null]");16    }17    public void should_return_toString_of_given_array_with_array_element() {18        Object[] o = new Object[]{ "foo", new Object[]{ "bar", "baz" } };19        String s = toStringOf(o);20        assertThat(s).isEqualTo("[foo, [bar, baz]]");21    }22    public void should_return_toString_of_given_array_with_array_element_having_null_element() {23        Object[] o = new Object[]{ "foo", new Object[]{ "bar", null } };24        String s = toStringOf(o);25        assertThat(s).isEqualTo("[foo, [bar, null]]");26    }27    public void should_return_toString_of_given_array_with_array_element_having_array_element() {28        Object[] o = new Object[]{ "foo", new Object[]{ "bar", new Object[]{ "baz" } } };29        String s = toStringOf(o);30        assertThat(s).isEqualTo("[foo, [bar, [baz]]]");31    }32    public void should_return_toString_of_given_array_with_array_element_having_array_element_having_null_element() {33        Object[] o = new Object[]{ "foo", new Object[]{ "bar", new Object[]{ null } } };34        String s = toStringOf(o);

retainAll

Using AI Code Generation

1import java.util.ArrayList;2import java.util.Arrays;3import java.util.Collection;4import java.util.List;5import org.assertj.core.api.Assertions;6import org.assertj.core.presentation.StandardRepresentation;7public class StandardRepresentation_toStringOf_Test {8	public static void main(String[] args) {9		StandardRepresentation standardRepresentation = new StandardRepresentation();10		List<String> list = new ArrayList<String>();11		list.add("A");12		list.add("B");13		list.add("C");14		list.add("D");15		list.add("E");16		List<String> list2 = new ArrayList<String>();17		list2.add("A");18		list2.add("B");19		list2.add("C");20		list2.add("D");21		list2.add("E");22		list2.add("F");23		list.retainAll(list2);24		System.out.println(list);25	}26}27list.addAll(list2);

retainAll

Using AI Code Generation

1  public void should_use_toString_of_elements_when_toString_is_overridden() {2    List<String> list = new ArrayList<>();3    list.add("Luke");4    list.add("Yoda");5    assertThat(list).hasToString("[Luke, Yoda]");6  }7}

retainAll

Using AI Code Generation

1import java.util.ArrayList;2import java.util.List;3import java.util.stream.Collectors;4import java.util.stream.Stream;5public class RemoveDuplicates {6    public static void main(String[] args) {7        List<String> list = Stream.of("a", "b", "a", "c", "d", "d", "e", "f", "g", "h", "i", "j", "i", "k", "l", "m", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z")8                .collect(Collectors.toList());9        System.out.println("List with duplicates: " + list);10        list = new ArrayList<>(list);11        list.retainAll(Stream.of("a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z")12                .collect(Collectors.toSet()));13        System.out.println("List without duplicates: " + list);14    }15}

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