Best Assertj code snippet using org.assertj.core.presentation.StandardRepresentation_toStringOf_Test.listIterator
Source:StandardRepresentation_toStringOf_Test.java
...460 public int lastIndexOf(Object o) {461 return list.lastIndexOf(o);462 }463 @Override464 public ListIterator<T> listIterator() {465 return list.listIterator();466 }467 @Override468 public ListIterator<T> listIterator(int index) {469 return list.listIterator(index);470 }471 @Override472 public List<T> subList(int fromIndex, int toIndex) {473 return list.subList(fromIndex, toIndex);474 }475 }476 private static Stream<Arguments> durations() {477 return Stream.of(arguments(Duration.of(1L, MILLIS), "0.001S"),478 arguments(Duration.of(1234L, MILLIS), "1.234S"),479 arguments(Duration.of(3_661_001L, MILLIS), "1H1M1.001S"));480 }481 private String toStringOf(Object o) {482 return STANDARD_REPRESENTATION.toStringOf(o);483 }...
listIterator
Using AI Code Generation
1 List<String> list = new ArrayList<>();2 list.add("one");3 list.add("two");4 list.add("three");5 ListIterator<String> iter = list.listIterator();6 while (iter.hasNext()) {7 String element = iter.next();8 System.out.println(element);9 }10 List<String> list = new ArrayList<>();11 list.add("one");12 list.add("two");13 list.add("three");14 ListIterator<String> iter = list.listIterator();15 while (iter.hasNext()) {16 String element = iter.next();17 System.out.println(element);18 }19 }20}21add(E e)22hasNext()23hasPrevious()24next()25nextIndex()26previous()27previousIndex()28remove()29set(E e)
listIterator
Using AI Code Generation
1 assertThat(listIterator).toString().isEqualTo("[1, 2, 3, 4, 5]");2 assertThat(listIterator).toString().isEqualTo("[1, 2, 3, 4, 5]");3 assertThat(listIterator).toString().isEqualTo("[1, 2, 3, 4, 5]");4 assertThat(listIterator).toString().isEqualTo("[1, 2, 3, 4, 5]");5 assertThat(listIterator).toString().isEqualTo("[1, 2, 3, 4, 5]");6 assertThat(listIterator).toString().isEqualTo("[1, 2, 3, 4, 5]");
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