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How to use start method of com.foo.rpc.examples.spring.db.base.DbBaseService class

Best EvoMaster code snippet using com.foo.rpc.examples.spring.db.base.DbBaseService.start

Source:DbBaseController.java

...19            put(DbBaseService.Iface.class.getName(), client);20        }});21    }22    @Override23    public String startClient() {24        String url = "http://localhost:"+getSutPort()+"/dbbase";25        try {26            // init client27            TTransport transport = new THttpClient(url);28            TProtocol protocol = new TBinaryProtocol(transport);29            client = new DbBaseService.Client(protocol);30        } catch (TTransportException e) {31            e.printStackTrace();32        }33        return url;34    }35    @Override36    public void resetStateOfSUT()  {37        try {...

start

Using AI Code Generation

1package com.foo.rpc.examples.spring.db.base;2import org.springframework.context.support.ClassPathXmlApplicationContext;3public class DbBaseService {4    public static void main(String[] args) {5        ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(new String[] {"spring-db-base.xml"});6        context.start();7        System.out.println("DbBaseService started...");8        try {9            Thread.sleep(Integer.MAX_VALUE);10        } catch (InterruptedException e) {11            e.printStackTrace();12        }13    }14}15package com.foo.rpc.examples.spring.db.base;16import org.springframework.context.support.ClassPathXmlApplicationContext;17public class DbBaseService {18    public static void main(String[] args) {19        ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(new String[] {"spring-db-base.xml"});20        context.start();21        System.out.println("DbBaseService started...");22        try {23            Thread.sleep(Integer.MAX_VALUE);24        } catch (InterruptedException e) {25            e.printStackTrace();26        }27    }28}29package com.foo.rpc.examples.spring.db.base;30import org.springframework.context.support.ClassPathXmlApplicationContext;31public class DbBaseService {32    public static void main(String[] args) {33        ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext(new String[] {"spring-db-base.xml"});34        context.start();35        System.out.println("DbBaseService started...");36        try {

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