How to use ResponseConverter class of org.openqa.selenium.netty.server package

just do it:

public class stacktest  {


@Test
public void teststackquestion() {

    boolean actual = true;
    boolean expected = false;
   Assert.assertEquals(actual, expected);

}


@AfterMethod
public void afterMethod(ITestResult result)
{
    try
 {
    if(result.getStatus() == ITestResult.SUCCESS)
    {

        //Do something here
        System.out.println("passed **********");
    }

    else if(result.getStatus() == ITestResult.FAILURE)
    {
         //Do something here
        System.out.println("Failed ***********");

    }

     else if(result.getStatus() == ITestResult.SKIP ){

        System.out.println("Skiped***********");

    }
}
   catch(Exception e)
   {
     e.printStackTrace();
   }

}

}

Use findElements instead of findElement.

findElements will return an empty list if no matching elements are found instead of an exception.

To check that an element is present, you could try this

Boolean isPresent = driver.findElements(By.yourLocator).size() > 0

This will return true if at least one element is found and false if it does not exist.

The official documentation recommends this method:

findElement should not be used to look for non-present elements, use findElements(By) and assert zero length response instead.

You can get the element color(Background color of element) by:

element.getCssValue("background-color");

You can get the element text/caption color by:

element.getCssValue("color");

For example if you want to get the background and text color of "Sign in" button for LinkedIn, the code is as follows:

driver.get("https://www.linkedin.com/");
        String buttonColor = driver.findElement(By.name("submit")).getCssValue("background-color");
        String buttonTextColor = driver.findElement(By.name("submit")).getCssValue("color");
        System.out.println("Button color: " + buttonColor);
        System.out.println("Text color " + buttonTextColor);

You want to wait until the alert is present before switching to it, similar to your 3rd row. Reference.

EDIT: try:

new WebDriverWait(driver, 60)
        .ignoring(NoAlertPresentException.class)
        .until(ExpectedConditions.alertIsPresent());

Alert al = driver.switchTo().alert();
al.accept();

In Webdriver, you should use driver.switchTo().defaultContent(); to get out of a frame. You need to get out of all the frames first, then switch into outer frame again.

// between step 4 and step 5
// remove selenium.selectFrame("relative=up");
driver.switchTo().defaultContent(); // you are now outside both frames
driver.switchTo().frame("cq-cf-frame");
// now continue step 6
driver.findElement(By.xpath("//button[text()='OK']")).click(); 

Create cookies using the Java API as follows:

Cookie ck = new Cookie("name", "value");
driver.manage().addCookie(ck);

Create cookies using the Python API as follows:

driver.add_cookie({'name': 'foo', 'value': 'bar'})

Like you said since the xpath for the next button is the same on every page it won't work. It's working as coded in that it does wait for the element to be displayed but since it's already displayed then the implicit wait doesn't apply because it doesn't need to wait at all. Why don't you use the fact that the url changes since from your code it appears to change when the next button is clicked. I do C# but I guess in Java it would be something like:

WebDriver driver = new FirefoxDriver();
String startURL = //a starting url;
String currentURL = null;
WebDriverWait wait = new WebDriverWait(driver, 10);

foo(driver,startURL);

/* go to next page */
if(driver.findElement(By.xpath("//*[@id='someID']")).isDisplayed()){
    String previousURL = driver.getCurrentUrl();
    driver.findElement(By.xpath("//*[@id='someID']")).click();  
    driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);

    ExpectedCondition e = new ExpectedCondition<Boolean>() {
          public Boolean apply(WebDriver d) {
            return (d.getCurrentUrl() != previousURL);
          }
        };

    wait.until(e);
    currentURL = driver.getCurrentUrl();
    System.out.println(currentURL);
} 

This is how I got it to work finally !!

 driver.findElement(By.cssSelector("label[for='surveyForm\\:surveyUrlType\\:1']")).click()

This is what I have been doing and it has worked so far for me.

ChromeOptions chromeOptions = new ChromeOptions();
chromeOptions.addArgument("--log-level=3");
chromeOptions.addArgument("--silent");
WebDriver driver = new ChromeDriver(chromeOptions);