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How to use test_any_of method in pyshould

Best Python code snippet using pyshould_python

parser.py

Source:parser.py

...32            if first_char not in symbols:33                return self.ERROR, "expected any of '" + symbols + "', got " + first_char, input_str34            return self.OK, first_char, input_str[1:]35        return inner36def test_any_of():37    symbols = ""38    p = Parser(any_of(symbols))39    tag, p_res, leftover = p("")40    assert tag == Parser.ERROR41    assert p_res == Parser.eof42    assert leftover == ""43    44    symbols = "abc"45    p = Parser(any_of(symbols))46    tag, p_res, leftover = p("ai")47    assert tag == Parser.OK48    assert p_res == "a"49    assert leftover == "i"50    tag, p_res, leftover = p("ia")51    assert tag == Parser.ERROR52    assert leftover == "ia"53    54def chain(*parsers):55    """56    : param parsers: list of Parser instances to be combined57    : return: superposition of parsers58    """59    def shallow_parse(self, input_str):60        return self.OK, "", input_str61    62    def inner(self, input_str):63        tag, res, leftover = shallow_parse(self, input_str)64        res_list = []65        for parser in parsers:66            tag, res, leftover = parser(leftover)67            res_list.append(res)68            if tag != Parser.OK:69                return tag, res_list, leftover70        return self.OK, res_list, leftover71    return inner72def test_chain():73    input_str = "()."74    p = Parser(chain())75    tag, res, leftover = p(input_str)76    assert tag == Parser.OK77    assert len(res) == 078    assert leftover == input_str79    80    p1, p2 = Parser(any_of("(")), Parser(any_of(")"))81    p = Parser(chain(p1, p2))82    tag, res, leftover = p(input_str)83    assert tag == Parser.OK84    assert len(res) == 285    assert res[0] == input_str[0]86    assert res[1] == input_str[1]87    assert leftover == input_str[2:]88def choice(*parsers):89    """90    : param parsers: list of Parser instances, each is applied to input string independently91    : return: result of first parser in 'parsers' that returns OK as a tag, else informs user about failure of all92    """93    choice.err_no_match = "none matched"94    95    def inner(self, input_str):96        for parser in parsers:97            tag, res, leftover = parser(input_str)98            if tag == Parser.OK:99                return tag, res, leftover100        return self.ERROR, choice.err_no_match, input_str101    return inner102                103def test_choice():104    p = Parser(choice(Parser(any_of(".")), Parser(any_of("!"))))105    for symbol in ".!?":106        tag, res, leftover = p(symbol)107        if symbol in ".!":108            assert tag == Parser.OK109            assert res == symbol110            assert leftover == ""111        else:112            assert tag == Parser.ERROR113            assert res == choice.err_no_match114            assert leftover == symbol115def many(parser, empty=True):116    """117    : param parser: a Parser instance which is to be applied to input string repeatedly until it returns ERROR118    : return: result - list of 'parser' results119    """120    def inner(self, input_str):121        res_list = []122        tag, res, leftover = parser(input_str)123        while tag == Parser.OK:124            res_list.append(res)125            tag, res, leftover = parser(leftover)126        if empty:127            return Parser.OK, res_list, leftover128        return Parser.ERROR, res, input_str # if 'empty'==false, returns error message returned by 'parser'129    return inner130def test_many():131    p = Parser(many(Parser(any_of("bcehiktrqu "))))132    input_str = "the quick red fox jumps over the lazy brown dog"133    tag, res, leftover = p(input_str)134    assert tag == Parser.OK135    assert len(res) == 12136    assert leftover == input_str[12:]    137if __name__ == "__main__":138    test_any_of()139    test_chain()140    test_choice()141    test_many()...

test_helper_func.py

Source:test_helper_func.py

...4    assert(line_to_string(l) == "XXX")5def even(x):6  '''Liefert True, falls x eine gerade Zahl ist.'''7  return x % 2 == 08def test_any_of():9    a1 = [1,3,5,7,9]10    a2 = [1,2,3,4,5]11    assert(any_of(a1,even) == False)12    assert(any_of(a2,even) == True)13def test_board_to_string():14    b = [["1","2","3"],["4","5","6"],["7","8","9"]]15    assert(board_to_string(b) == "1 | 2 | 3\n--+---+--\n4 | 5 | 6\n--+---+--\n7 | 8 | 9")16def test_helper_functions():17    test_line_to_string()18    test_any_of()19    test_board_to_string()20  21if __name__ == "__main__":22    test_helper_functions()...

test_pipelines.py

Source:test_pipelines.py

...4    v = module.AllOf(module.Int(min=0), module.Int(max=10))5    assert benchmark(v, 1) == 16# =============================================================================7@pytest.mark.benchmark(group="OneOf")8def test_any_of(module, benchmark):9    v = module.OneOf(module.Int(min=0), module.Int(min=10))...

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