How to use _handle_route method in Playwright Python

From what I understand, you have a page that has content within an iframe. You want to use Playwright to access elements within that frame.

The official docs to handle frames: Official docs: https://playwright.dev/docs/frames#frame-objects

You could then try something like this:

// Locate element inside frame
const iframeButton = await page.frameLocator('iFrame').locator("button:has-text(\"Add New User\")");
await iframeButton.click();

Notice that the example has the iFrame tag as locator, but you could and should use something more accurate like and id, name or url.

page.hover(selector[, options])

After that you can do

page.waitForSlector(selector,{timeout:6000})

And then do what you need for your elem. You can read this:

https://playwright.dev/docs/api/class-page#page-hover

Try this:

if (page.is_visible(XPATH)):
    page.click(XPATH)

Or you can make the code cleaner like this:

try:
    page.click(XPATH)
except:
    pass

Looks like soup is unable to find anything and its returning None and Nonetype has no text property

The error looks here for soup in clothes: as you have overridden the soup parser

PS:

You can use get_text() to extract the text

price = soup.find('span', {'class' : 'price'}).get_text()

Sometimes you may have to use contents depending on the return type

price = soup.find('span', {'class' : 'price'}).contents[0]

I have come up with a solution in Node js puppeteer and I think it work the same way in python. As far as why the button isn't being pressed, I have no idea. But, what does work is entering an address and then clicking the first address suggestion.

Here is my code:

const puppeteer = require('puppeteer');
async function start(){
    const browser = await puppeteer.launch()
    const page = await browser.newPage()
    await page.goto("https://www.ubereats.com/ca")
    await page.type("#location-typeahead-home-input", "Address")
    await page.waitForSelector('#location-typeahead-home-item-0');
    await page.click("#location-typeahead-home-item-0")
    await page.waitForNavigation()

    console.log(page.url())
    await browser.close()
}

start()

How about checking if the element is clickable: https://playwright.dev/docs/api/class-locator#locator-click

use trial option and if it returns true continue execution

  await page.click(First_Row_Download, , {trial:true})

You are supposed to use sync_playwright as a context managers:

from playwright.sync_api import sync_playwright
print('debug1')

with sync_playwright() as p:
    print('debug2')
    browser = p.firefox.launch(headless=False)
    print('debug3')
    page = browser.new_page()
    page.goto("http://whatsmyuseragent.org/")
    page.screenshot(path="example.png")
    browser.close()

Output

debug1
debug2
debug3

See playwright documentation for python here

Edit (specific to OP)

As a last ditch effort, try these steps in order:

1. Run pip install -U pip
2. Run pip uninstall plawyright
3. Run pip cache remove playwright
4. Run pip install playwright

Keep in mind that if you have installed multiple versions of python, use the PATH variable defined for pip for the version of python you want to install playwright in. Lastly, try changing the browser you use with playwright. So instead of browser = p.firefox.launch(headless=False), use browser = p.chromium.launch(headless=False)

What dialog.accept() does is to accept (click OK) the dialog. page.click("OK") only works with DOM (HTML) elements, not with browser dialogs.

Not sure exactly if by "browser to show up" you refer at the fact that you need the browser to not run in headless mode.

There are two possible ways:

1. Install Playwright Test for VSCode as suggest by @MingJie-MSFT. You'll have a Show browser checkbox there in case you want to run your tests headless or not
2. In the config file, for use, add:

headless: false

Example for both options