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How to use test_hashable_dict method in localstack

Best Python code snippet using localstack_python

common.py

Source:common.py

...126	def __key(self):127		return tuple((k,self[k]) for k in sorted(self))128	def __hash__(self):129		return 5130def test_hashable_dict():131	print('test_hashable_dict()')132	cls = HashableDict133	cls = BadHashableDict134	a = cls()135	a[0] = 0136	a[1] = 1137	b = cls()138	b[0] = 0139	b[1] = 1140	c = cls()141	c[0] = 0142	c[1] = 1143	144	d = {}145	146	d[a] = "a"147	148	print(d)149	print(d[a])150	print(d[b])151	152	a[0] = 666153	154	print(d[b])...

test_collections.py

Source:test_collections.py

...31    assert "z" not in d132    with pytest.raises(Exception) as exc:33        d1["foo"] = "bar"34    exc.match("does not support item assignment")35def test_hashable_dict():36    d1 = HashableJsonDict({"a": ["b"], "c": 1})37    d2 = HashableJsonDict({"a": "b"})38    d3 = HashableJsonDict({"c": 1, "a": ["b"]})39    d4 = HashableJsonDict({})40    assert len({d1, d2, d3}) == 241    assert {d1, d2, d3} == {d1, d2} == {d2, d3}42    assert {d1, d3} == {d3, d1}43    assert {d1, d1} == {d3, d3}44    assert {d1, d2, d3} != {d1}45    assert {d1, d2, d3} != {d2}46    assert {d1, d2, d3} != {d1, d3}47    assert {d4, d4} == {d4}48    with pytest.raises(Exception) as exc:49        d1["foo"] = "bar"...

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