How to use get_object_acl method in localstack

Best Python code snippet using localstack_python

get_object_acl.py

Source:get_object_acl.py Github

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1import logging2import boto33from botocore.exceptions import ClientError4def get_object_acl(bucket_name, object_name):5 """Retrieve the access control list of an Amazon S3 object.6 :param bucket_name: string7 :param object_name: string8 :return: Dictionary defining the object's access control policy consisting9 of owner and grants. If error, return None.10 """11 # Retrieve the bucket ACL12 s3 = boto3.client('s3')13 try:14 response = s3.get_object_acl(Bucket=bucket_name, Key=object_name)15 except ClientError as e:16 # AllAccessDisabled error == bucket not found17 logging.error(e)18 return None19 # Return both the Owner and Grants keys20 # The Owner and Grants settings together form the Access Control Policy.21 # The Grants alone form the Access Control List.22 return {'Owner': response['Owner'], 'Grants': response['Grants']}23def main():24 """Exercise get_object_acl()"""25 # Assign these values before running the program26 test_bucket_name = 'BUCKET_NAME'27 test_object_name = 'OBJECT_NAME'28 # Set up logging29 logging.basicConfig(level=logging.DEBUG,30 format='%(levelname)s: %(asctime)s: %(message)s')31 # Retrieve the object's current access control list32 acl = get_object_acl(test_bucket_name, test_object_name)33 if acl is None:34 exit(-1)35 # Output the object ACL grantees and permissions36 for grantee in acl['Grants']:37 # The grantee type determines the grantee_identifier38 grantee_type = grantee['Grantee']['Type']39 if grantee_type == 'CanonicalUser':40 grantee_identifier = grantee['Grantee']['DisplayName']41 elif grantee_type == 'AmazonCustomerByEmail':42 grantee_identifier = grantee['Grantee']['EmailAddress']43 elif grantee_type == 'Group':44 grantee_identifier = grantee['Grantee']['URI']45 else:46 grantee_identifier = 'Unknown'...

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