How to use postorder method in avocado

Best Python code snippet using avocado_python

offer-33.py

Source:offer-33.py Github

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1from typing import List2# 二叉搜索树: 左子树上所有节点的值不大于其根节点3# 右子树上所有节点的值不小于其根节点4# 任意节点的左右子树也分别为二叉搜索树5# 二叉搜索树的后序遍历6# 后序遍历: 左 - 右 - 中7class Solution:8 def verifyPostorder(self, postorder: List[int]) -> bool:9 # 二叉搜索树的性质：10 # 如果左子树不空，左子树的所有节点的值小于根节点的值。11 # 如果右子树不空，则右子树所有节点的值大于根节点的值。12 # 当 postorder 为空的时候返回 True13 if postorder == []: return True14 n = len(postorder)15 # 找到第一个大于根节点的数，如果这个是二叉搜索树的话，这个数之后的数都是属于右子树，这个数之前的数都是属于左子树16 for i in range(n):17 if postorder[i] > postorder[-1]:18 break19 # postorder[-1] 是当前后序遍历的根节点20 # 并且按照上面的遍历方法来看，这里的left_tree里不会出现大于根节点的数21 left_tree = postorder[:i]22 right_tree = postorder[i:n - 1]23 # 判断right_tree里是否有小于根节点的数，有的话返回False24 for num in right_tree:25 if num < postorder[-1]:26 return False...

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2020-06-09-中等-二叉搜索树的后序遍历序列.py

Source:2020-06-09-中等-二叉搜索树的后序遍历序列.py Github

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1# 输入一个整数数组，判断该数组是不是某二叉搜索树的后序遍历结果。2# 如果是则返回 true，否则返回 false。3# 假设输入的数组的任意两个数字都互不相同。4# 思路：5# 一棵树的后序遍历：[左子树部分 右子树部分 根]6# 递归7def verifyPostorder(postorder):8 if len(postorder) <= 1:9 return True10 root = postorder.pop() 11 for index in range(len(postorder)+1): # +1很重要12 leftPostorderList = postorder[:index]13 rightpostorderList = postorder[index:]14 if leftPostorderList == []:15 if (root <= min(rightpostorderList)) and verifyPostorder(rightpostorderList):16 return True17 else:18 continue19 if rightpostorderList == []:20 if (root >= max(leftPostorderList)) and verifyPostorder(leftPostorderList):21 return True22 else:23 continue 24 if (root >= max(leftPostorderList)) and (root <= min(rightpostorderList)):25 if verifyPostorder(leftPostorderList) and verifyPostorder(rightpostorderList):26 return True27 else:28 continue29 return False30postorderList1 = [1,6,3,2,5] # 输出：False31postorderList2 = [1,3,2,6,5] # 输出：True32postorderList3 = [4, 6, 7, 5] # 输出：True33print(verifyPostorder(postorderList1))34print(verifyPostorder(postorderList2))...

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33.py

Source:33.py Github

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1def judge(postorder):2 if len(postorder)<=1:3 return True4 root = postorder[-1]5 index = len(postorder)6 for i in range(len(postorder)):7 if postorder[i]>root:8 index = i9 print(i)10 break11 for i in range(index,len(postorder),1):12 if postorder[i]<root:13 return False14 if index==len(postorder):15 return judge(postorder[:index-1])16 return judge(postorder[:index]) and judge(postorder[index:len(postorder)-1])17if __name__ == '__main__':18 postorder = [4, 6, 7, 5]19 print(sum(postorder))20 res = judge(postorder)...

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