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How to use beSortedWith method of io.kotest.matchers.sequences.matchers class

Best Kotest code snippet using io.kotest.matchers.sequences.matchers.beSortedWith

matchers.kt

Source:matchers.kt

...173         { "Sequence $snippet should not be sorted" }174      )175   }176}177infix fun <T> Sequence<T>.shouldBeSortedWith(comparator: Comparator<in T>) = this should beSortedWith(comparator)178infix fun <T> Sequence<T>.shouldBeSortedWith(cmp: (T, T) -> Int) = this should beSortedWith(cmp)179fun <T> beSortedWith(comparator: Comparator<in T>): Matcher<Sequence<T>> = sortedWith(comparator)180fun <T> beSortedWith(cmp: (T, T) -> Int): Matcher<Sequence<T>> = sortedWith(cmp)181fun <T> sortedWith(comparator: Comparator<in T>): Matcher<Sequence<T>> = sortedWith { a, b ->182   comparator.compare(a, b)183}184fun <T> sortedWith(cmp: (T, T) -> Int): Matcher<Sequence<T>> = object : Matcher<Sequence<T>> {185   override fun test(value: Sequence<T>): MatcherResult {186      @Suppress("UNUSED_DESTRUCTURED_PARAMETER_ENTRY")187      val failure = value.zipWithNext().withIndex().firstOrNull { (i, it) -> cmp(it.first, it.second) > 0 }188      val snippet = value.joinToString(",", limit = 10)189      val elementMessage = when (failure) {190         null -> ""191         else -> ". Element ${failure.value.first} at index ${failure.index} shouldn't precede element ${failure.value.second}"192      }193      return MatcherResult(194         failure == null,195         { "Sequence $snippet should be sorted$elementMessage" },196         { "Sequence $snippet should not be sorted" }197      )198   }199}200infix fun <T> Sequence<T>.shouldNotBeSortedWith(comparator: Comparator<in T>) = this shouldNot beSortedWith(comparator)201infix fun <T> Sequence<T>.shouldNotBeSortedWith(cmp: (T, T) -> Int) = this shouldNot beSortedWith(cmp)202infix fun <T> Sequence<T>.shouldHaveSingleElement(t: T) = this should singleElement(t)203infix fun <T> Sequence<T>.shouldNotHaveSingleElement(t: T) = this shouldNot singleElement(t)204fun <T> singleElement(t: T) = object : Matcher<Sequence<T>> {205   override fun test(value: Sequence<T>) = MatcherResult(206      value.count() == 1 && value.first() == t,207      { "Sequence should be a single element of $t but has ${value.count()} elements" },208      { "Sequence should not be a single element of $t" }209   )210}211infix fun <T> Sequence<T>.shouldHaveCount(count: Int) = this should haveCount(count)212infix fun <T> Sequence<T>.shouldNotHaveCount(count: Int) = this shouldNot haveCount(213   count)214infix fun <T> Sequence<T>.shouldHaveSize(size: Int) = this should haveCount(size)215infix fun <T> Sequence<T>.shouldNotHaveSize(size: Int) = this shouldNot haveCount(size)...

beSortedWith

Using AI Code Generation

1val list = listOf(1, 2, 3, 4, 5)2list should beSortedWith { a, b -> a <= b }3val list = listOf(1, 2, 3, 4, 5)4list should beSortedWith { a, b -> a <= b }5val map = mapOf("a" to 1, "b" to 2, "c" to 3, "d" to 4, "e" to 5)6map should beSortedWith { a, b -> a.value <= b.value }7val list = listOf(1, 2, 3, 4, 5)8list should beSortedWith { a, b -> a <= b }9val list = listOf(1, 2, 3, 4, 5)10list should beSortedWith { a, b -> a <= b }11val list = listOf(1, 2, 3, 4, 5)12list should beSortedWith { a, b -> a <= b }13val map = mapOf("a" to 1, "b" to 2, "c" to 3, "d" to 4, "e" to 5)14map should beSortedWith { a, b -> a.value <= b.value }15val list = listOf(1, 2, 3, 4, 5)16list should beSortedWith { a, b -> a <= b }17val list = listOf(1, 2, 3, 4, 5)

beSortedWith

Using AI Code Generation

1val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }2result should beSortedWith { a, b -> a > b }3val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }4result should beSortedWith { a, b -> a > b }5val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }6result should beSortedWith { a, b -> a > b }7val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }8result should beSortedWith { a, b -> a > b }9val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }10result should beSortedWith { a, b -> a > b }11val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }12result should beSortedWith { a, b -> a > b }13val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }14result should beSortedWith { a, b -> a > b }15val result = listOf(2, 1, 3).asSequence().beSortedWith { a, b -> a > b }

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