Best Kotest code snippet using io.kotest.matchers.ints.IntMatchers.beGreaterThan
beGreaterThan
Using AI Code Generation
1assertThat(10).beGreaterThan(5)2assertThat(5).beLessThan(10)3assertThat(5).beLessThanOrEqual(5)4assertThat(5).beGreaterThanOrEqual(5)5assertThat(5).beBetween(1, 10)6assertThat(5).beCloseTo(5, 1)7assertThat(10).bePositive()8assertThat(-10).beNegative()9assertThat(0).beZero()10assertThat(10).beEven()11assertThat(11).beOdd()12assertThat(10).beOneOf(10, 20, 30)13assertThat(10).beNoneOf(11, 21, 31)14assertThat(10).beIn(10, 20, 30)15assertThat(10).beNotIn(11, 21, 31)16assertThat(10).beInClosed
beGreaterThan
Using AI Code Generation
1assertThat( 4 ).beGreaterThan( 3 )2assertThat( 3 ).beLessThan( 4 )3assertThat( 3 ).beLessThanOrEqual( 4 )4assertThat( 4 ).beGreaterThanOrEqual( 3 )5assertThat( 4 ).beInRange( 3.. 5 )6assertThat( 4 ).bePositive()7assertThat( -4 ).beNegative()8assertThat( 0 ).beZero()9assertThat( 1 ).beOneOf( 1 , 2 , 3 )10assertThat( 1 ).beOneOf( intArrayOf( 1 , 2 , 3 ))11assertThat( 1 ).beNoneOf( 2 , 3 , 4 )12assertThat( 1 ).beNoneOf( intArrayOf( 2 , 3 , 4 ))13assertThat( 4 ).beEven()14assertThat( 3 ).beOdd()15assertThat( 4 ).beDivisibleBy(
beGreaterThan
Using AI Code Generation
1println(10.beGreaterThan(5))2println(10.beLessThan(20))3println(10.beBetween(5, 20))4println(-10.beNegative())5println(10.bePositive())6println(0.beZero())
beGreaterThan
Using AI Code Generation
1fun `should return true when the first number is greater than the second number`(){2 firstNumber.shouldBeGreaterThan(secondNumber)3}4fun `should return true when the first number is less than the second number`(){5 firstNumber.shouldBeLessThan(secondNumber)6}7fun `should return true when the first number is greater than or equal to the second number`(){8 firstNumber.shouldBeGreaterThanOrEqualTo(secondNumber)9}10fun `should return true when the first number is less than or equal to the second number`(){11 firstNumber.shouldBeLessThanOrEqualTo(secondNumber)12}13fun `should return true when the first number is between the second and third numbers`(){14 firstNumber.shouldBeBetween(secondNumber, thirdNumber)15}16fun `should return true when the first number is between the second and third numbers and inclusive is true`(){17 firstNumber.shouldBeBetween(secondNumber, thirdNumber, true)18}19fun `should return true when the first number is between the second and third numbers and inclusive is false`(){20 firstNumber.shouldBeBetween(secondNumber, thirdNumber, false)21}
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