How to use hasCommonAncestor method in qawolf

Best JavaScript code snippet using qawolf

getCommonAncestorsGraphRoblox.js

Source:getCommonAncestorsGraphRoblox.js Github

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...14// (4, 8), (4, 9), (9, 11), (14, 4), (13, 12), (12, 9)15// ]16// Write a function that takes the graph, as well as two of the individuals in our dataset, as its inputs and returns true if and only if they share at least one ancestor.17// Sample input and output:18// hasCommonAncestor(parentChildPairs1, 3, 8) => false19// hasCommonAncestor(parentChildPairs1, 5, 8) => true20// hasCommonAncestor(parentChildPairs1, 6, 8) => true21// hasCommonAncestor(parentChildPairs1, 6, 9) => true22// hasCommonAncestor(parentChildPairs1, 1, 3) => false23// hasCommonAncestor(parentChildPairs1, 3, 1) => false24// hasCommonAncestor(parentChildPairs1, 7, 11) => true25// hasCommonAncestor(parentChildPairs1, 6, 5) => true26// hasCommonAncestor(parentChildPairs1, 5, 6) => true27// Additional example: In this diagram, 4 and 12 have a common ancestor of 11.28// 1129// / \30// 10 1231// / \32// 1 2 533// \ / / \34// 3 6 735// \ \36// 4 837// parentChildPairs2 = [38// (11, 10), (11, 12), (2, 3), (10, 2), (10, 5),39// (1, 3), (3, 4), (5, 6), (5, 7), (7, 8),40// ]41// hasCommonAncestor(parentChildPairs2, 4, 12) => true42// hasCommonAncestor(parentChildPairs2, 1, 6) => false43// hasCommonAncestor(parentChildPairs2, 1, 12) => false44// n: number of pairs in the input45const parentChildPairs1 = [46 [1, 3], [2, 3], [3, 6], [5, 6], [5, 7], [4, 5],47 [4, 8], [4, 9], [9, 11], [14, 4], [13, 12], [12, 9]48];49const parentChildPairs2 = [50 [11, 10], [11, 12], [2, 3], [10, 2], [10, 5],51 [1, 3], [3, 4], [5, 6], [5, 7], [7, 8]52];53function hasCommonAncestor(parentChildPairs, p, q) {54 // hash tiene como keys los hijos y una propiedad de parents55 let hash = {};56 for(let i = 0; i < parentChildPairs.length; i++) {57 let elem = parentChildPairs[i];58 let parent = elem[0];59 let child = elem[1];60 if(child in hash) {61 hash[child].count++;62 hash[child].parents.push(parent);63 } else {64 hash[child] = {count: 1, parents: [parent]}65 }66 }67 // Hash with childrens with node as parents68 console.log(hash);69 // Parents all both nodes (p and q)70 let ancestorP = getNodeAncestors(p, hash);71 let ancestorQ = getNodeAncestors(q, hash);72 // Convert those into arrays73 let arrayP = Array.from(ancestorP);74 let arrayQ = Array.from(ancestorQ);75 // Get the common ancestors76 let intersection = arrayP.filter((item) => arrayQ.includes(item));77 // These are the common ancestor they have78 console.log(intersection);79 return intersection.length > 0;80 81}82// BFS83function getNodeAncestors(p, hash) {84 let set = new Set();85 let queue = [];86 queue.push(p);87 while(queue.length) {88 let size = queue.length;89 for(let i = 0; i < size; i++) {90 let node = queue.shift();91 // Add node as parent of the node we are looking for92 if(!set.has(node) && node !== p) {93 set.add(node);94 }95 // Check for the parents of all nodes96 if(node in hash) {97 let parents = hash[node].parents;98 for(let i = 0; i < parents.length; i++) {99 queue.push(parents[i]);100 }101 }102 }103 }104 return set;105}106// Correct al section107console.log(hasCommonAncestor(parentChildPairs1, 3, 8));108// console.log(hasCommonAncestor(parentChildPairs1, 5, 8));109// console.log(hasCommonAncestor(parentChildPairs1, 6, 8));110// console.log(hasCommonAncestor(parentChildPairs1, 6, 9));111// console.log(hasCommonAncestor(parentChildPairs1, 1, 3));112// console.log(hasCommonAncestor(parentChildPairs1, 3, 1));113// console.log(hasCommonAncestor(parentChildPairs1, 7, 11));114// console.log(hasCommonAncestor(parentChildPairs1, 6, 5));115// console.log(hasCommonAncestor(parentChildPairs1, 5, 6));116// console.log(hasCommonAncestor(parentChildPairs2, 4, 12));117// console.log(hasCommonAncestor(parentChildPairs2, 1, 6));...

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parentChildTraverse.js

Source:parentChildTraverse.js Github

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...5]6const checkAncestors = (arr1, arr2) => {7 return arr1.some((val) => arr2.includes(val));8}9function hasCommonAncestor(pairs, child1, child2) {10 const ancestors1 = [];11 const ancestors2 = [];12 const bfs = (child, arr) => {13 const q = [child]; // 614 while (q.length > 0) {15 let curr = q.shift(); // 616 for (let [par, chil] of pairs) {17 if (curr === chil) {18 // push ancestors + push to queue19 arr.push(par);20 q.push(par);21 }22 }23 }24 }25 bfs(child1, ancestors1);26 bfs(child2, ancestors2);27 return (28 checkAncestors(ancestors1, ancestors2) ||29 checkAncestors(ancestors2, ancestors1)30 );31}32console.log(hasCommonAncestor(parentChildPairs, 6, 8)); // true: 433console.log(hasCommonAncestor(parentChildPairs, 5, 8)); // true: 434console.log(hasCommonAncestor(parentChildPairs, 11, 6)); // true: 435console.log(hasCommonAncestor(parentChildPairs, 3, 1)); // false: 36console.log(hasCommonAncestor(parentChildPairs, 12, 4)); // false: 37// first get all parents of 638// first get all parents of 8...

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ejercicio_9.js

Source:ejercicio_9.js Github

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...15Write a function that, for two given16individuals in our dataset, returns true if17and only if they share at least one ancestor.18Sample input and output:19hasCommonAncestor(parentChildPairs, 3, 8) => false20hasCommonAncestor(parentChildPairs, 5, 8) => true21hasCommonAncestor(parentChildPairs, 6, 8) => true22hasCommonAncestor(parentChildPairs, 1, 3) => false...

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Using AI Code Generation

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1const { hasCommonAncestor } = require("qawolf");2const { chromium } = require("playwright");3(async () => {4 const browser = await chromium.launch();5 const context = await browser.newContext();6 const page = await context.newPage();7 const element1 = await page.$("input[name=q]");8 const element2 = await page.$("input[name=btnK]");9 const result = await hasCommonAncestor(element1, element2);10 console.log(result);11 await browser.close();12})();

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Using AI Code Generation

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1const { hasCommonAncestor } = require('qawolf');2const { isDescendantOf } = require('qawolf');3const { isAncestorOf } = require('qawolf');4const { isSiblingOf } = require('qawolf');5const { isChildOf } = require('qawolf');6const { isParentOf } = require('qawolf');7const { isAdjacentTo } = require('qawolf');8const { isInsideOf } = require('qawolf');9const { isOutsideOf } = require('qawolf');10const { isNear } = require('qawolf');11const { isFar } = require('qawolf');12const { isCloseTo } = require('qawolf');13const { isFarFrom } = require('qawolf');14const { isAbove } = require('qawolf');15const { isBelow } = require('qawolf');16const { isLeftOf } = require('qawolf');17const { isRightOf } = require('qawolf');18const { isAlignedTo } = require('qawolf');19const { isAlignedLeftOf } = require('qawolf');20const { isAlignedRight

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Using AI Code Generation

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1const { hasCommonAncestor } = require("qawolf");2const parent = document.createElement("div");3const child = document.createElement("div");4parent.appendChild(child);5console.log(hasCommonAncestor(parent, child));6console.log(hasCommonAncestor(parent, document.createElement("div")));7console.log(hasCommonAncestor(parent, parent));8console.log(hasCommonAncestor(document.createElement("div"), document.createElement("div")));9console.log(hasCommonAncestor(document.createElement("div"), null));10console.log(hasCommonAncestor(null, document.createElement("div")));11console.log(hasCommonAncestor(null, null));12console.log(hasCommonAncestor());13console.log(hasCommonAncestor(null));14console.log(hasCommonAncestor(null, null, null));15console.log(hasCommonAncestor(null, null, null, null));16console.log(hasCommonAncestor(null, null, null, null, null));17console.log(hasCommonAncestor(null, null, null, null, null, null));18console.log(hasCommonAncestor(null, null, null, null, null, null, null));19console.log(hasCommonAncestor(null, null, null, null, null, null, null, null));20console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null));21console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null, null));22console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null, null, null));23console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null, null, null, null));24console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null, null, null, null, null));25console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null, null, null, null, null, null));26console.log(hasCommonAncestor(null, null, null, null, null, null, null, null, null

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Using AI Code Generation

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1const qawolf = require("qawolf");2const { chromium } = require("playwright");3(async () => {4 const browser = await chromium.launch();5 const context = await browser.newContext();6 const page = await context.newPage();7 await page.click("input[name=\"q\"]");8 await page.fill("input[name=\"q\"]", "qawolf");9 await page.click("input[name=\"q\"]");10 await page.keyboard.press("Enter");11 await page.click("text=QA Wolf: Record and generate end-to-end tests");

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