How to use First method of rod Package

Best Rod code snippet using rod.First

dynamic_programing.go

Source:dynamic_programing.go Github

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1package dance2import "fmt"3/​/​ 1.自顶向下递归实现4/​/​ 现在需要明确一个概念，切割完成之后的钢条中的每段的长度都不会超过 price 表中最大的长度5func cutRod(price []int, length int) int {6 if length == 0 {7 return 08 }9 max := -110 /​/​ i 表示的是切去的部分，切去的部分肯定是可以定价的，不会超过 price 表中最大的长度11 /​/​ i 又必须不能大于总长度 length12 for i := 1; i < len(price) && i <= length; i++ {13 max = getMax(max, price[i]+cutRod(price, length-i))14 }15 return max16}17/​/​ 3.自底向上法18func ButtonUpCutRod(price []int, length int) int {19 result := make([]int, length+1)20 result[0] = 021 for i := 1; i <= length; i++ {22 q := -123 /​/​ i 表示的是切去的部分，切去的部分肯定是可以定价的，不会超过 price 表中最大的长度24 /​/​又必须不能大于总长度 length25 for j := 1; j <= i && j <= len(price)-1; j++ {26 q = getMax(q, price[j]+result[i-j])27 }28 result[i] = q29 }30 return result[length]31}32/​/​ 扩展自底向上法33func ExtendedButtonUpCutRod(price []int, len int) ([]int, []int) {34 result, firstCut := make([]int, len+1), make([]int, len+1)35 for i := 1; i < len+1; i++ {36 q := -137 for j := 0; j < i; j++ {38 t := result[j] + price[i-j]39 if t >= q {40 q = t41 firstCut[i] = i - j42 }43 }44 result[i] = q45 }46 return result, firstCut47}48func PrintButtonUpCutRod(price []int, len int) {49 result, firstCut := ExtendedButtonUpCutRod(price, len)50 fmt.Println("amount:", result[len])51 fmt.Println("list:")52 for len > 0 {53 current := firstCut[len]54 fmt.Println(current)55 len -= current56 }57}58/​/​ 2. 自带备忘的自顶向下发法59func MemoizedCutRod(price []int, length int) int {60 result := make([]int, length+1)61 return memoizedCutRod(price, result, length)62}63func memoizedCutRod(price []int, result []int, length int) int {64 if length == 0 {65 return 066 }67 if result[length] > 0 {68 return result[length]69 }70 max := -171 /​/​ i 在这里是被切去的部分，i不大于总长度且不大于 price 表中最大的长度72 for i := 1; i <= length && i < len(price); i++ {73 max = getMax(max, price[i]+memoizedCutRod(price, result, length-i))74 }75 result[length] = max76 return max77}78func ExtendedMemoizedCutRod(price []int, len int) ([]int, []int) {79 firstCut, result := make([]int, len+1), make([]int, len+1)80 extendedMemoizedCutRod(price, firstCut, result, len)81 return firstCut, result82}83func extendedMemoizedCutRod(price []int, firstCut []int, result []int, len int) int {84 max := -185 for i := 0; i < len+1; i++ {86 max = getMax(max, extendedMemoizedCutRod(price, firstCut, result, i)+1)87 }88 return 089}90/​/​面试题 08.01. 三步问题91/​/​ 这是很基础的动态规划92/​/​ 我们考虑现在已经n阶上面，有几种方法一步走到n阶呢，我们可以在n-1阶上走一步1阶到n,也可以在 n-2 阶走一步2阶，也可以在n-3阶走一步3阶93/​/​ 那么 一共有 f(n) = f(n-1)+f(n-2)+f(n-3)种走法94/​/​ 动态规划有两要素：最优子结构，重叠子问题95/​/​ 这里有多少种走法就是该问题的唯一解，也可以理解为最优解96/​/​ n 的解是 n-1,n-2,n-3 子问题的解的和97/​/​ 重叠子问题，如果递归算法反复求解子问题，我们就称最优化问题具有重叠子问题性质98/​/​ f(n) = f(n-1)+f(n-2)+f(n-3)99/​/​ f(n-1) = f(n-2)+f(n-3)+f(n-4)100/​/​ 可以看出求解子问题并不会引出更多的子问题101func waysToStep(n int) int {102 result := make([]int, n+1)103 result[0] = 1104 result[1] = 1105 for i := 2; i <= n; i++ {106 count := 0107 /​/​ 注意这里 j可以等于i,因为如果 n <=3 我们一步就可以走到108 for j := 1; j <= i && j <= 3; j++ {109 count += result[i-j]110 count %= 1000000007111 }112 result[i] = count113 }114 return result[n]115}116/​/​ 1143. 最长公共子序列117/​/​ 最长公共子序列与最长公共子串的区别就是公共子序列中的元素在原始字符串 str1,str2 不需要连续，118/​/​ 例如： A,C,A 就是 A,B,D,C,B,A 和 A,C,B,A 的一个公共子串，但不是最长公共子序列。A,C,B,A 是最长公共子序列119/​/​ 而最长公共子串是 B,A120/​/​ 因为公共子序列的性质，我们可以刻画最长公共子序列的性质，str1,str2 的最长子序列为 k，121/​/​ 如果 str1[-1] == str2[-1], 那么 k[:-1] 是 str1[:-1] 和 str2[:-1]的最长公共子串122/​/​ 如果 str1[-1] != str2[-1]123/​/​ 如果 str1[-1] != k[-1] 那么 k 是 str1[:-1] 和 str2 的 LCS124/​/​ 如果 str2[-1] != k[-1] 那么 k 是 str1 和 str2[:-1] 的 LCS125/​/​ 假设 str1,str2 长度分别为 rows,column,我们创建一个 c[rows][column] 的两维数组,126/​/​ c[i][j]表示 str1 前 i 个元素与 str2 前 j 个元素的 LCS 的长度 ，例如，str1 前4个元素是 A,B,D,C ,str2 前 3个元素是 A,C,B127/​/​ 那么他们的 LCS 就是 A,B c[4][3] = 2128func longestCommonSubsequence(text1 string, text2 string) int {129 len1, len2 := len(text1), len(text2)130 c := make([][]int, len1+1)131 for i := 0; i < len1+1; i++ {132 c[i] = make([]int, len2+1)133 }134 for i := 0; i < len1+1; i++ {135 c[i][0] = 0136 }137 for j := 0; j < len2+1; j++ {138 c[0][j] = 0139 }140 for i := 1; i < len1+1; i++ {141 for j := 1; j < len2+1; j++ {142 if text1[i-1] == text2[j-1] {143 c[i][j] = c[i-1][j-1] + 1144 } else if c[i-1][j] > c[i][j-1] {145 c[i][j] = c[i-1][j]146 } else {147 c[i][j] = c[i][j-1]148 }149 }150 }151 return c[len1][len2]152}153/​/​ 计算 LCS 的长度154/​/​ c[i][j]为 Xi 和 Yj LCS 的长度，Xi 和 Yj 有一个为 0 c[i][j]==0155/​/​156/​/​157func LCSLength(text1, text2 string) ([][]int, [][]byte) {158 len1, len2 := len(text1), len(text2)159 c, b := make([][]int, len1+1), make([][]byte, len1+1)160 for i := 0; i < len1+1; i++ {161 c[i] = make([]int, len2+1)162 b[i] = make([]byte, len2+1)163 }164 for i := 1; i <= len1; i++ {165 for j := 1; j <= len2; j++ {166 if text1[i-1] == text2[j-1] {167 c[i][j] = c[i-1][j-1] + 1168 b[i][j] = '\\'169 } else if c[i-1][j] >= c[i][j-1] {170 c[i][j] = c[i-1][j]171 b[i][j] = '^'172 } else {173 c[i][j] = c[i][j-1]174 b[i][j] = '<'175 }176 }177 }178 return c, b179}180func PrintLCS(b [][]byte, text1 string, i, j int) []byte {181 buffer := make([]byte, 0)182 var printLCS func([][]byte, string, int, int)183 printLCS = func(b [][]byte, text1 string, i, j int) {184 switch b[i][j] {185 case '^':186 printLCS(b, text1, i-1, j)187 case '<':188 printLCS(b, text1, i, j-1)189 case '\\':190 buffer = append(buffer, text1[i-1])191 printLCS(b, text1, i-1, j-1)192 }193 }194 printLCS(b, text1, i, j)195 buffLen := len(buffer)196 reverse := make([]byte, buffLen)197 for i := buffLen - 1; i >= 0; i-- {198 reverse[buffLen-1-i] = buffer[i]199 }200 return reverse201}202/​/​ 疑问，最长公共子序列和最长公共子串的共同点在哪里，是否可以转化？203/​/​ 我认为最长公共子串是最长公共子序列的特殊情况。特殊点是公共子串每个字符之间没有其他不同的字符。所以公共子序列的算法在204/​/​ 公共子串上同样试用。205/​/​ 最长公共子串206/​/​ 最优子结构 有限子问题域207/​/​ 现在想如何实现最优子结构208func longestCommonSubstring(text1 string, text2 string) int {209 return 0210}...

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hinged_rod.go

Source:hinged_rod.go Github

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1package solver2import (3 "github.com/​mokiat/​gomath/​dprec"4 "github.com/​mokiat/​lacking/​game/​physics"5)6var _ physics.DBConstraintSolver = (*HingedRod)(nil)7/​/​ NewHingedRod creates a new HingedRod constraint solution.8func NewHingedRod() *HingedRod {9 result := &HingedRod{10 length: 1.0,11 }12 result.DBJacobianConstraintSolver = physics.NewDBJacobianConstraintSolver(result.calculate)13 return result14}15/​/​ HingedRod represents the solution for a constraint16/​/​ that keeps two bodies tied together with a hard link17/​/​ of specific length.18type HingedRod struct {19 *physics.DBJacobianConstraintSolver20 primaryAnchor dprec.Vec321 secondaryAnchor dprec.Vec322 length float6423}24/​/​ PrimaryAnchor returns the attachment point of the link25/​/​ on the primary body.26func (r *HingedRod) PrimaryAnchor() dprec.Vec3 {27 return r.primaryAnchor28}29/​/​ SetPrimaryAnchor changes the attachment point of the link30/​/​ on the primary body.31func (r *HingedRod) SetPrimaryAnchor(anchor dprec.Vec3) *HingedRod {32 r.primaryAnchor = anchor33 return r34}35/​/​ SecondaryAnchor returns the attachment point of the link36/​/​ on the secondary body.37func (r *HingedRod) SecondaryAnchor() dprec.Vec3 {38 return r.secondaryAnchor39}40/​/​ SetSecondaryAnchor changes the attachment point of the link41/​/​ on the secondary body.42func (r *HingedRod) SetSecondaryAnchor(anchor dprec.Vec3) *HingedRod {43 r.secondaryAnchor = anchor44 return r45}46/​/​ Length returns the link length.47func (r *HingedRod) Length() float64 {48 return r.length49}50/​/​ SetLength changes the link length.51func (r *HingedRod) SetLength(length float64) *HingedRod {52 r.length = length53 return r54}55func (r *HingedRod) calculate(ctx physics.DBSolverContext) (physics.PairJacobian, float64) {56 firstRadiusWS := dprec.QuatVec3Rotation(ctx.Primary.Orientation(), r.primaryAnchor)57 secondRadiusWS := dprec.QuatVec3Rotation(ctx.Secondary.Orientation(), r.secondaryAnchor)58 firstAnchorWS := dprec.Vec3Sum(ctx.Primary.Position(), firstRadiusWS)59 secondAnchorWS := dprec.Vec3Sum(ctx.Secondary.Position(), secondRadiusWS)60 deltaPosition := dprec.Vec3Diff(secondAnchorWS, firstAnchorWS)61 normal := dprec.BasisXVec3()62 if deltaPosition.SqrLength() > sqrEpsilon {63 normal = dprec.UnitVec3(deltaPosition)64 }65 return physics.PairJacobian{66 Primary: physics.Jacobian{67 SlopeVelocity: dprec.NewVec3(68 -normal.X,69 -normal.Y,70 -normal.Z,71 ),72 SlopeAngularVelocity: dprec.NewVec3(73 -(normal.Z*firstRadiusWS.Y - normal.Y*firstRadiusWS.Z),74 -(normal.X*firstRadiusWS.Z - normal.Z*firstRadiusWS.X),75 -(normal.Y*firstRadiusWS.X - normal.X*firstRadiusWS.Y),76 ),77 },78 Secondary: physics.Jacobian{79 SlopeVelocity: dprec.NewVec3(80 normal.X,81 normal.Y,82 normal.Z,83 ),84 SlopeAngularVelocity: dprec.NewVec3(85 normal.Z*secondRadiusWS.Y-normal.Y*secondRadiusWS.Z,86 normal.X*secondRadiusWS.Z-normal.Z*secondRadiusWS.X,87 normal.Y*secondRadiusWS.X-normal.X*secondRadiusWS.Y,88 ),89 },90 },91 deltaPosition.Length() - r.length92}...

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dynamic_test.go

Source:dynamic_test.go Github

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...23func TestPrintButtonUpCutRod(t *testing.T) {24 price := []int{0, 1, 5, 8, 9, 10, 17, 17, 20, 24, 30}25 expectResult := struct {26 Amount []int27 First []int28 }{29 []int{0, 1, 5, 8, 10, 13, 17, 18, 22, 25, 30},30 []int{0, 1, 2, 3, 2, 2, 6, 1, 2, 3, 10},31 }32 amount, first := ExtendedButtonUpCutRod(price, 10)33 for i := 0; i < 11; i++ {34 if expectResult.Amount[i] != amount[i] || expectResult.First[i] != first[i] {35 t.Fatal("unexpect result")36 }37 }38 PrintButtonUpCutRod(price[:], 10)39}40func TestMemoizedCutRod(t *testing.T) {41 price := []int{0, 1, 5, 8, 9, 10, 17, 17, 20, 24, 30}42 for i := 0; i <= 10; i++ {43 if MemoizedCutRod(price, i) != cutRod(price, i) {44 t.Errorf("length:%d,MemoizedCutRod=%d,cutRod=%d", i, MemoizedCutRod(price, i), cutRod(price, i))45 }46 }47}48func TestWaysToStep(t *testing.T) {...

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First

Using AI Code Generation

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1import "fmt"2func main() {3r.First()4}5import "fmt"6type rod struct {7}8func (r rod) First() {9fmt.Println("First")10}11func (r rod) Second() {12fmt.Println("Second")13}14func (r rod) Third() {15fmt.Println("Third")16}

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First

Using AI Code Generation

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1import "fmt"2type rod struct{3}4func (r rod) First() int{5}6func main(){7fmt.Println(r.First())8}

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First

Using AI Code Generation

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1import "fmt"2type rod struct {3}4func (r rod) first() {5fmt.Println("First method of rod")6}7func main() {8r := rod{length: 10}9r.first()10}11import "fmt"12type rod struct {13}14func (r *rod) first() {15fmt.Println("First method of rod")16}17func main() {18r := rod{length: 10}19r.first()20}

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First

Using AI Code Generation

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1import (2func main() {3 browser := rod.New().Connect()4 input := page.Element("input[name=q]")5 input.Clear()6 input.Input("rod")7 input.Submit()8 page.WaitLoad()9 result := page.Element(".g>.r>a")10 href, _ := result.Attribute("href")11 fmt.Println(href)12}13Rod is a tool to help you interact with the web page. It is a Go library that controls the browser like a human. It is built on top of CDP (Chrome Devtools Protocol) and can be used to automate browser tasks like crawling, scraping, unit testing, etc. Rod is a tool to help you interact with the web page. It is a Go library that controls the browser like a human. It is built on

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First

Using AI Code Generation

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1import "fmt"2type rod struct {3}4func (r rod) First() {5fmt.Println("Length of rod is",r.length)6}7func main() {8r := rod{length: 5}9r.First()10}11import "fmt"12type rod struct {13}14func (r *rod) First() {15}16func main() {17r := rod{length: 5}18r.First()19fmt.Println(r.length)20}

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First

Using AI Code Generation

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1import (2func main() {3 l := launcher.New().Headless(false)4 browser := rod.New().ControlURL(l).MustConnect()5 page.MustElement(`#lst-ib`).MustInput("rod").MustPress(input.Enter)6 page.MustWaitLoad()7 title := page.MustElement(`#rso .g>.rc .r>a`).MustText()8 fmt.Println(title)9}

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First

Using AI Code Generation

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1import (2func main() {3 var r = rod.Rod{Length: 5}4 fmt.Println("Length of rod is:", r.First())5}6import (7func main() {8 var r = rod.Rod{Length: 5}9 fmt.Println("Length of rod is:", r.Second())10}11import (12func main() {13 var r = rod.Rod{Length: 5}14 fmt.Println("Length of rod is:", r.Third())15}16import (17func main() {18 var r = rod.Rod{Length: 5}19 fmt.Println("Length of rod is:", r.Fourth())20}21import (22func main() {23 var r = rod.Rod{Length: 5}24 fmt.Println("Length of rod is:", r.Fifth())25}26import (27func main() {28 var r = rod.Rod{Length: 5}29 fmt.Println("Length of rod is:", r.Sixth())30}31import (32func main() {33 var r = rod.Rod{Length: 5}34 fmt.Println("Length of rod is:", r.Seventh())35}36import (37func main() {38 var r = rod.Rod{Length: 5}39 fmt.Println("Length of rod is:", r.Eighth())40}41import (42func main() {43 var r = rod.Rod{Length

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First

Using AI Code Generation

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1import (2func main() {3 fmt.Println("Rod length:", first.RodLength)4 fmt.Println("Rod diameter:", first.RodDiameter)5 fmt.Println("Rod weight:", first.RodWeight)6 fmt.Println("Rod cost:", first.RodCost)7 fmt.Println("Rod first:", first.First())8 fmt.Println("Rod second:", first.Second())9 fmt.Println("Rod third:", first.Third())10}

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First

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1import "fmt"2import "github.com/​go-rod/​rod"3func main() {4b := rod.New().MustConnect()5title := page.MustElement("title")6fmt.Println(title.MustText())7b.MustClose()8}

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