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How to use ConvertToResourceName method of Telerik.JustMock.Core.Castle.Core.Resource.AssemblyResource class

Best JustMockLite code snippet using Telerik.JustMock.Core.Castle.Core.Resource.AssemblyResource.ConvertToResourceName

AssemblyResource.cs

Source:AssemblyResource.cs

...62		private Stream CreateResourceFromUri(CustomUri resourcex, String path)63		{64			if (resourcex == null) throw new ArgumentNullException("resourcex");65			assemblyName = resourcex.Host;66			resourcePath = ConvertToResourceName(assemblyName, resourcex.Path);67			Assembly assembly = ObtainAssembly(assemblyName);68			String[] names = assembly.GetManifestResourceNames();69			String nameFound = GetNameFound(names);70			if (nameFound == null)71			{72				resourcePath = resourcex.Path.Replace('/', '.').Substring(1);73				nameFound = GetNameFound(names);74			}75			if (nameFound == null)76			{77				String message = String.Format(CultureInfo.InvariantCulture, "The assembly resource {0} could not be located", resourcePath);78				throw new ResourceException(message);79			}80			basePath = ConvertToPath(resourcePath);81			return assembly.GetManifestResourceStream(nameFound);82		}83		private string GetNameFound(string[] names)84		{85			string nameFound = null;86			foreach(String name in names)87			{88				if (String.Compare(resourcePath, name, StringComparison.OrdinalIgnoreCase) == 0)89				{90					nameFound = name;91					break;92				}93			}94			return nameFound;95		}96		private string ConvertToResourceName(String assembly, String resource)97		{98			assembly = GetSimpleName(assembly);99			// TODO: use path for relative name construction100			return String.Format(CultureInfo.CurrentCulture, "{0}{1}", assembly, resource.Replace('/', '.'));101		}102		private string GetSimpleName(string assembly)103		{104			int indexOfComma = assembly.IndexOf(',');105			if(indexOfComma<0)106			{107				return assembly;108			}109			return assembly.Substring(0, indexOfComma);110		}...

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Collections.Generic;3using System.Linq;4using System.Text;5using System.Threading.Tasks;6using Telerik.JustMock.Core.Castle.Core.Resource;7{8    {9        static void Main(string[] args)10        {11            AssemblyResource resource = new AssemblyResource();12            string resourceName = resource.ConvertToResourceName("ConsoleApplication1.Program");13            Console.WriteLine(resourceName);14        }15    }16}17But I am getting the error "The type or namespace name 'Telerik' could not be found (are you missing a using directive or an assembly reference?)"

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Collections.Generic;3using System.Linq;4using System.Text;5using System.Threading.Tasks;6using Telerik.JustMock.Core.Castle.Core.Resource;7{8    {9        static void Main(string[] args)10        {11            AssemblyResource resource = new AssemblyResource(typeof(Program).Assembly);12            Console.WriteLine(resource.ConvertToResourceName("JustMockUnitTest.Program"));13            Console.WriteLine(resource.ConvertToResourceName("JustMockUnitTest.Program.Main"));14        }15    }16}

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Collections.Generic;3using System.Linq;4using System.Text;5using System.Threading.Tasks;6using Telerik.JustMock.Core.Castle.Core.Resource;7{8    {9        static void Main(string[] args)10        {11            string resName = AssemblyResource.ConvertToResourceName(typeof(Program), "JustMockUnitTest.Resources.File1.txt");12            Console.WriteLine(resName);13            Console.ReadLine();14        }15    }16}

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Reflection;3using Telerik.JustMock.Core.Castle.Core.Resource;4{5    {6        static void Main(string[] args)7        {8            var assembly = Assembly.GetExecutingAssembly();9            var resourceName = AssemblyResource.ConvertToResourceName(assembly, "4.cs");10            Console.WriteLine(resourceName);11        }12    }13}14Hello Tsvetina,Thank you for your response. I tried to use the code you provided, but it doesn't work. The resourceName is still "4.cs". I have attached the code I am using. I am using the latest version of JustMock (2015.3.1024.1). I have also attached the stack trace of the exception I am getting. Please let me know if you have any other ideas. Thanks,James

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Collections.Generic;3using System.Linq;4using System.Text;5using System.Threading.Tasks;6using Telerik.JustMock.Core.Castle.Core.Resource;7using Telerik.JustMock.Core.Castle.Core.Internal;8{9    {10        static void Main(string[] args)11        {12            var assembly = typeof(Program).Assembly;13            var resourceName = AssemblyResource.ConvertToResourceName(assembly, "Test.txt");14            Console.WriteLine(resourceName);15            Console.ReadKey();16        }17    }18}

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Reflection;3using System.Resources;4using System.Collections;5using Telerik.JustMock.Core.Castle.Core.Resource;6{7    public static void Main()8    {9        Assembly assembly = Assembly.GetExecutingAssembly();10        ResourceManager resourceManager = new ResourceManager("4", assembly);11        string name = resourceManager.BaseName;12        string fileName = assembly.Location;13        string resourceFileName = AssemblyResource.ConvertToResourceName(fileName, name);14        Console.WriteLine(resourceFileName);15    }16}

ConvertToResourceName

Using AI Code Generation

1using System;2using System.IO;3using System.Reflection;4using Telerik.JustMock.Core.Castle.Core.Resource;5{6    {7        static void Main(string[] args)8        {9            string assemblyName = "ConsoleApplication1.exe";10            string fileName = "1.txt";11            string resourceName = AssemblyResource.ConvertToResourceName(assemblyName, fileName);12            Console.WriteLine(resourceName);13            Console.ReadLine();14        }15    }16}17public abstract Stream GetResourceStream();18public abstract void ReleaseResourceStream(Stream stream);19public AssemblyResource(Assembly assembly, string name);20public AssemblyResource(Assembly assembly, string name, string fileName);21public AssemblyResource(Assembly assembly, string name, string fileName, string assemblyName);22Assembly assembly = Assembly.GetExecutingAssembly();23string name = "ConsoleApplication1.1.txt";24string fileName = "1.txt";25string assemblyName = "ConsoleApplication1.exe";26AssemblyResource assemblyResource = new AssemblyResource(assembly, name, fileName, assemblyName);

ConvertToResourceName

Using AI Code Generation

1using System;2using System.Reflection;3using Telerik.JustMock.Core.Castle.Core.Resource;4using System.IO;5{6    {7        static void Main(string[] args)8        {9            Assembly assembly = Assembly.GetExecutingAssembly();10            AssemblyResource resource = new AssemblyResource(assembly, "4.cs");11            string resourceName = resource.ConvertToResourceName();12            Console.WriteLine(resourceName);13        }14    }15}16using System;17using System.Reflection;18using Telerik.JustMock.Core.Castle.Core.Resource;19using System.IO;20{21    {22        static void Main(string[] args)23        {24            Assembly assembly = Assembly.GetExecutingAssembly();25            AssemblyResource resource = new AssemblyResource(assembly, "5.cs");26            string resourceName = resource.ConvertToResourceName();27            Console.WriteLine(resourceName);28        }29    }30}31using System;32using System.Reflection;33using Telerik.JustMock.Core.Castle.Core.Resource;34using System.IO;35{36    {37        static void Main(string[] args)38        {39            Assembly assembly = Assembly.GetExecutingAssembly();40            AssemblyResource resource = new AssemblyResource(assembly, "6.cs");41            string resourceName = resource.ConvertToResourceName();42            Console.WriteLine(resourceName);43        }44    }45}46using System;47using System.Reflection;48using Telerik.JustMock.Core.Castle.Core.Resource;49using System.IO;50{51    {52        static void Main(string[] args)53        {54            Assembly assembly = Assembly.GetExecutingAssembly();55            AssemblyResource resource = new AssemblyResource(assembly, "7.cs");56            string resourceName = resource.ConvertToResourceName();57            Console.WriteLine(resourceName);58        }59    }60}

ConvertToResourceName

Using AI Code Generation

1using System;2using Telerik.JustMock.Core;3{4    {5        public static void ConvertToResourceName()6        {7            string resourceName = Telerik.JustMock.Core.Castle.Core.Resource.AssemblyResource.ConvertToResourceName("JustMock.ElevatedExamples", "AssemblyResource");8            Console.WriteLine(resourceName);9        }10    }11}12using System;13using Telerik.JustMock.Core;14{15    {16        public static void ConvertToResourceName()17        {18            string resourceName = Telerik.JustMock.Core.Castle.Core.Resource.AssemblyResource.ConvertToResourceName("JustMock.ElevatedExamples", "AssemblyResource", "ConvertToResourceName");19            Console.WriteLine(resourceName);20        }21    }22}23using System;24using Telerik.JustMock.Core;25{26    {27        public static void ConvertToResourceName()28        {29            string resourceName = Telerik.JustMock.Core.Castle.Core.Resource.AssemblyResource.ConvertToResourceName("JustMock.ElevatedExamples", "AssemblyResource", "ConvertToResourceName", "cs");30            Console.WriteLine(resourceName);31        }32    }33}34using System;35using Telerik.JustMock.Core;36{37    {38        public static void ConvertToResourceName()39        {40            string resourceName = Telerik.JustMock.Core.Castle.Core.Resource.AssemblyResource.ConvertToResourceName("JustMock.ElevatedExamples", "AssemblyResource", "ConvertToResourceName", "cs");

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