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How to use ProviderName_OfPropertyChain method of Atata.Tests.DataProvision.SubjectTests class

Best Atata code snippet using Atata.Tests.DataProvision.SubjectTests.ProviderName_OfPropertyChain

SubjectTests.cs

Source:SubjectTests.cs

...104            public void ProviderName_OfProperty() =>105                _subject.ResultOf(x => x.Count)106                    .ProviderName.Should().Be("subject.Count => result");107            [Test]108            public void ProviderName_OfPropertyChain() =>109                _subject.ResultOf(x => x.Keys.Count)110                    .ProviderName.Should().Be("subject.Keys.Count => result");111            [Test]112            public void ProviderName_OfFunction() =>113                _subject.ResultOf(x => x.ContainsKey("a"))114                    .ProviderName.Should().Be("subject.ContainsKey(\"a\") => result");115            [Test]116            public void ProviderName_OfFunction_WithOutParameter()117            {118                int value;119                _subject.ResultOf(x => x.TryGetValue("a", out value))120                    .ProviderName.Should().Be("subject.TryGetValue(\"a\", out value) => result");121            }122            [Test]123            public void ProviderName_OfFunction_AfterAct() =>124                _subject125                    .Act(x => x.Add("d", 4))126                    .ResultOf(x => x.ContainsKey("d"))127                    .ProviderName.Should().Be("subject{ Add(\"d\", 4) }.ContainsKey(\"d\") => result");128            [Test]129            public void ProviderName_OfFunction_AfterMultipleActs() =>130                _subject131                    .Act(x => x.Add("d", 4))132                    .Act(x => x.Add("e", 5))133                    .ResultOf(x => x.ContainsKey("d"))134                    .ProviderName.Should().Be("subject{ Add(\"d\", 4); Add(\"e\", 5) }.ContainsKey(\"d\") => result");135            [Test]136            public void ProviderName_OfFunction_AfterResultOf() =>137                _subject.ResultOf(x => x.Keys.Where(key => key != "z"))138                    .ResultOf(x => x.First())139                    .ProviderName.ToResultSubject()140                    .Should.Equal("subject.Keys.Where(key => key != \"z\") => result.First() => result");141            [Test]142            public void ProviderName_OfFunction_AfterSubjectOf() =>143                _subject.SubjectOf(x => x.Keys.Where(key => key != "z"))144                    .ResultOf(x => x.First())145                    .ProviderName.ToResultSubject()146                    .Should.Equal("subject.Keys.Where(key => key != \"z\").First() => result");147            [Test]148            public void ProviderName_OfIndexer() =>149                _subject.ResultOf(x => x["a"])150                    .ProviderName.Should().Be("subject[\"a\"] => result");151        }152        [TestFixture]153        public class SubjectOf154        {155            private Subject<Dictionary<string, int>> _subject;156            [SetUp]157            public void SetUpTest() =>158                _subject = CreateDictionarySubject();159            [Test]160            public void ProviderName_OfProperty() =>161                _subject.SubjectOf(x => x.Count)162                    .ProviderName.Should().Be("subject.Count");163            [Test]164            public void ProviderName_OfPropertyChain() =>165                _subject.SubjectOf(x => x.Keys.Count)166                    .ProviderName.Should().Be("subject.Keys.Count");167            [Test]168            public void ProviderName_OfFunction() =>169                _subject.SubjectOf(x => x.ContainsKey("a"))170                    .ProviderName.Should().Be("subject.ContainsKey(\"a\")");171            [Test]172            public void ProviderName_OfFunction_AfterAct() =>173                _subject174                    .Act(x => x.Add("d", 4))175                    .SubjectOf(x => x.ContainsKey("d"))176                    .ProviderName.Should().Be("subject{ Add(\"d\", 4) }.ContainsKey(\"d\")");177            [Test]178            public void ProviderName_OfFunction_AfterResultOf() =>...

ProviderName_OfPropertyChain

Using AI Code Generation

1public void ProviderName_OfPropertyChain()2{3    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);4    providerName.Should.Equal("Person.FirstName");5}6public void ProviderName_OfPropertyChain()7{8    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);9    providerName.Should.Equal("Person.FirstName");10}11public void ProviderName_OfPropertyChain()12{13    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);14    providerName.Should.Equal("Person.FirstName");15}16public void ProviderName_OfPropertyChain()17{18    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);19    providerName.Should.Equal("Person.FirstName");20}21public void ProviderName_OfPropertyChain()22{23    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);24    providerName.Should.Equal("Person.FirstName");25}26public void ProviderName_OfPropertyChain()27{28    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);29    providerName.Should.Equal("Person.FirstName");30}31public void ProviderName_OfPropertyChain()32{33    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);34    providerName.Should.Equal("Person.FirstName");35}36public void ProviderName_OfPropertyChain()37{38    var providerName = Subject.ProviderName.OfPropertyChain(x => x.Person.FirstName);

ProviderName_OfPropertyChain

Using AI Code Generation

1[Subject(typeof(DataProvision.SubjectTests))]2{3    public void ProviderName_OfPropertyChain()4    {5        var providerName = DataProviderName.Of<SubjectTests>(x => x.Property1.Property2.Property3);6        providerName.Should.Equal("Property1_Property2_Property3");7    }8}9[Subject(typeof(DataProvision.SubjectTests))]10{11    public void ProviderName_OfPropertyChain()12    {13        var providerName = DataProviderName.Of<SubjectTests>(x => x.Property1.Property2.Property3);14        providerName.Should.Equal("Property1_Property2_Property3");15    }16}17[Subject(typeof(DataProvision.SubjectTests))]18{19    public void ProviderName_OfPropertyChain()20    {21        var providerName = DataProviderName.Of<SubjectTests>(x => x.Property1.Property2.Property3);22        providerName.Should.Equal("Property1_Property2_Property3");23    }24}25[Subject(typeof(DataProvision.SubjectTests))]26{27    public void ProviderName_OfPropertyChain()28    {29        var providerName = DataProviderName.Of<SubjectTests>(x => x.Property1.Property2.Property3);30        providerName.Should.Equal("Property1_Property2_Property3");31    }32}33[Subject(typeof(DataProvision.SubjectTests))]34{35    public void ProviderName_OfPropertyChain()36    {

ProviderName_OfPropertyChain

Using AI Code Generation

1[Subject(nameof(DataProvision))]2{3    public void Should_be_the_expected_provider()4    {5        var providerName = SubjectTests.ProviderName_OfPropertyChain;6        providerName.Should.Equal("MyProvider");7    }8}

ProviderName_OfPropertyChain

Using AI Code Generation

1using System;2using Atata;3using NUnit.Framework;4using static Atata.Tests.DataProvision.SubjectTests;5{6    {7        public void PropertyNameOfTest()8        {9            var propertyChain = PropertyNameOf(ProviderName_OfPropertyChain());10            Assert.That(propertyChain, Is.EqualTo("Subject.ProviderName"));11        }12    }13}14at NUnit.Framework.Assert.That[TActual](TActual actual, IResolveConstraint expression, String message, Object[] args)15   at NUnit.Framework.Assert.That[TActual](TActual actual, IResolveConstraint expression, String message, Object[] args)16   at Atata.Tests.DataProvision.PropertyNameOfTests.PropertyNameOfTest() in C:\Users\user\Documents\Visual Studio 2017\Projects\Atata\src\Atata.Tests\DataProvision\PropertyNameOfTests.cs:line 1917using System;18using Atata;19using NUnit.Framework;20using static Atata.Tests.DataProvision.SubjectTests;21{

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