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How to use ReferenceXml class of NBi.Xml.Settings package

Best NBi code snippet using NBi.Xml.Settings.ReferenceXml

SharedDatasetXml.cs

...33                    if (!Parameters.Exists(p => p.Name == param.Name))34                        list.Add(param);35            return list;36        }37        public void AssignReferences(IEnumerable<ReferenceXml> references)38        {39            if (string.IsNullOrEmpty(Source))40                Source = Default.Report.Source;41            if (string.IsNullOrEmpty(Path))42                Path = Default.Report.Path;43            if (!string.IsNullOrEmpty(Source) && Source.StartsWith("@"))44                Source = InitializeFromReferences(references, Source, "source");45            if (!string.IsNullOrEmpty(Path) && Path.StartsWith("@"))46                Path = InitializeFromReferences(references, Path, "path");47        }48        protected virtual string InitializeFromReferences(IEnumerable<ReferenceXml> references, string refName, string attribute)49        {50            if (refName.StartsWith("@"))51                refName = refName.Substring(1);52            var refChoice = GetReference(references, refName);53            if (refChoice.Report == null)54                throw new NullReferenceException(string.Format("A reference named '{0}' has been found, but no element 'report' has been defined", refName));55            if (attribute=="source")56                return refChoice.Report.Source;57            if (attribute=="path")58                return refChoice.Report.Path;59            throw new ArgumentOutOfRangeException();60        }61        protected ReferenceXml GetReference(IEnumerable<ReferenceXml> references, string value)62        {63            if (references == null || references.Count() == 0)64                throw new InvalidOperationException("No reference has been defined for this constraint");65            var refChoice = references.FirstOrDefault(r => r.Name == value);66            if (refChoice == null)67                throw new IndexOutOfRangeException(string.Format("No reference named '{0}' has been defined.", value));68            return refChoice;69        }70    }71}...

NumericFormatXml.cs

Source: NumericFormatXml.cs

...1920        [XmlAttribute("ref")]21        public string Reference {get; set;}2223        internal void AssignReferences(IEnumerable<ReferenceXml> references)24        {25            if (!string.IsNullOrEmpty(Reference))26                InitializeFromReferences(references, Reference);27        }2829        protected virtual void InitializeFromReferences(IEnumerable<ReferenceXml> references, string value)30        {31            var refChoice = GetReference(references, value);3233            if (refChoice.NumericFormat==null)34                throw new NullReferenceException(string.Format("A reference named '{0}' has been defined, but it's numeric-format is not defined", value));3536            Initialize(refChoice.NumericFormat);37        }3839        protected void Initialize(INumericFormat format)40        {            41            DecimalDigits = format.DecimalDigits;42            DecimalSeparator = format.DecimalSeparator;43            GroupSeparator = format.GroupSeparator;44        }4546        protected ReferenceXml GetReference(IEnumerable<ReferenceXml> references, string value)47        {48            if (references == null || references.Count() == 0)49                throw new InvalidOperationException("No reference has been defined for this constraint");5051            var refChoice = references.FirstOrDefault(r => r.Name == value);52            if (refChoice == null)53                throw new IndexOutOfRangeException(string.Format("No reference named '{0}' has been defined.", value));54            return refChoice;55        }56        57        [XmlAttribute("decimal-digits")]58        public int DecimalDigits { get; set; }5960        [XmlAttribute("decimal-separator")]
...

PerspectiveXmlTest.cs

Source: PerspectiveXmlTest.cs

...21            perspectiveXml.Caption = "My Caption";22            perspectiveXml.Default = new DefaultXml() { ApplyTo = SettingsXml.DefaultScope.Assert, ConnectionString = "connStr" };23            perspectiveXml.Settings = new SettingsXml()24                {25                    References = new List<ReferenceXml>() 26                    { new ReferenceXml() 27                        { Name = "Bob", ConnectionString = "connStr" } 28                    }29                };3031            var serializer = new XmlSerializer(typeof(PerspectiveXml));32            var stream = new MemoryStream();33            var writer = new StreamWriter(stream, Encoding.UTF8);34            serializer.Serialize(writer, perspectiveXml);35            var content = Encoding.UTF8.GetString(stream.ToArray());36            writer.Close();37            stream.Close();3839            Debug.WriteLine(content);40
...

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